How do you solve #7- 3c = - 4c#?

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Answer 1 · 2016-11-19T13:53:49

#c = -7#

Perform the necessary mathematics to solve for #c# while keeping the equation balanced:

First, subtract 7 from each side of the equation:

#7 - 3c - 7 = -4c - 7#

#-3c + 0 = -4c - 7#

#-3c = -4c - 7#

Next, add #4c# to each side of the equation:

#-3c + 4c = -4c - 7 + 4c#

#(-3 + 4)c = -7 + 0#

#1c = -7#

#c = -7#