How do you solve #7( 4x + 2) + 3= - 67#?

1 Answer
Apr 17, 2017

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation by multiplying each term inside the parenthesis by the term outside the parenthesis:

#color(red)(7)(4x + 2) + 3 = -67#

#(color(red)(7) * 4x) + (color(red)(7) * 2) + 3 = -67#

#28x + 14 + 3 = -67#

#28x + 17 = -67#

Next, subtract #color(red)(17)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#28x + 17 - color(red)(17) = -67 - color(red)(17)#

#28x + 0 = -84#

#28x = -84#

Now, divide each side of the equation by #color(red)(28)# to solve for #x# while keeping the equation balanced:

#(28x)/color(red)(28) = -84/color(red)(28)#

#(color(red)(cancel(color(black)(28)))x)/cancel(color(red)(28)) = -3#

#x = -3#