First, expand the terms within the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:
#-7 - color(red)(6)(1 + 6x) < 275#
#-7 - (color(red)(6) xx 1) - (color(red)(6) xx 6x) < 275#
#-7 - 6 - 36x < 275#
#-13 - 36x < 275#
Now, add #color(red)(13)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:
#color(red)(13) - 13 - 36x < color(red)(13) + 275#
#0 - 36x < 288#
#-36x < 288#
Now, divide each side of the inequality by #color(blue)(-36)# to solve by #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:
#(-36x)/color(blue)(-36) color(red)(>) 288/color(blue)(-36)#
#(color(blue)(cancel(color(black)(-36)))x)/cancel(color(blue)(-36)) color(red)(>) -8#
#x > -8#