How do you solve #-7- 6( 1+ 6x ) < 275#?

1 Answer
Sep 18, 2017

See a solution process below:

Explanation:

First, expand the terms within the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

#-7 - color(red)(6)(1 + 6x) < 275#

#-7 - (color(red)(6) xx 1) - (color(red)(6) xx 6x) < 275#

#-7 - 6 - 36x < 275#

#-13 - 36x < 275#

Now, add #color(red)(13)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#color(red)(13) - 13 - 36x < color(red)(13) + 275#

#0 - 36x < 288#

#-36x < 288#

Now, divide each side of the inequality by #color(blue)(-36)# to solve by #x# while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse the inequality operator:

#(-36x)/color(blue)(-36) color(red)(>) 288/color(blue)(-36)#

#(color(blue)(cancel(color(black)(-36)))x)/cancel(color(blue)(-36)) color(red)(>) -8#

#x > -8#