How do you solve #7^x + 2 = 410#?

1 Answer
May 20, 2016

3.09

Explanation:

#7^x + 2 =410#

#7^x = 408#

Take the natural log of both sides,we get,

#ln(7^x) = ln (408)#

Using logarithm properties, we can bring the x exponent outside the ln

#xln(7) = ln (408)#

#x=ln(408) / ln(7)#

#=(6.0112)#/#(1.945) #

#3.09#