How do you solve #7^x=49#?

2 Answers
Sep 30, 2016

Answer:

#x=2#

Explanation:

#7^x=49#
#=> 7^x=7^2#
#=> x=2#

Answer:

#x=2#

Explanation:

By observation we can see that #x=2# because #7^2=49#. But let's solve this another way. We can do it using logs.

#7^x=49#

#log7^x=log49#

#xlog7=log(7xx7)#

#x=log(7xx7)/log7#

#x=(log7+log7)/log7#

#x=log7/log7+log7/log7=1+1=2#