How do you solve #7x + 2( 5+ 2x ) = 87#?

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Answer 1 · 2016-11-20T11:56:37

#x = 7#

To complete this problem you need to isolate and solve for #x# while keeping the equation balanced:

First expand the terms in parenthesis:

#7x + (2*5) + (2*2x) = 87#

#7x + 10 + 4x = 87#

Next, combine like terms:

#(7 + 4)x + 10 = 87#

#11x + 10 = 87#

Then, subtract 10 from each side of the equation:

#11x + 10 - 10 = 87 - 10#

#11x + 0 = 77#

#11x = 77#

Finally, divide each side of the equation by 11:

#(11x)/11 = 77/11#

#1x = 7#

#x = 7#