How do you solve #-7x + 2( x + 1) = 8( 1- x ) + x#?

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Answer 1 · 2016-12-16T09:58:05

#x=3#

#-7x+2(x+1)=8(1-x)+x#

#-7x+2*x+2*1=8*1-8*x+x#

#-7x+2x+2=8-8x+x#

#-5x+2=8-7x#

#-5x+7x=8-2#

#2x=6#

#(cancel(2)x)/cancel(2)=6/2#

#x=6/2#

#x=3#