# How do you solve (-7x^2)(x^4)?

Apr 10, 2015

Remember the general rule for combining exponents: ${b}^{p} \cdot {b}^{q} = {b}^{p + q}$

$\left(- 7 {x}^{2}\right) \left({x}^{4}\right)$

$= \left(- 7\right) \cdot \left({x}^{2}\right) \cdot \left({x}^{4}\right)$

$= \left(- 7\right) \left({x}^{2} \cdot {x}^{4}\right)$

$= \left(- 7\right) \left({x}^{6}\right)$

$= - 7 {x}^{6}$