# How do you solve (7x)/3 < 2?

May 2, 2015

The answer is $x < \frac{6}{7}$.

Solve $\frac{7 x}{3} < 2$ .

Multiply both sides by $3$.

$\frac{7 x}{\cancel{3}} \cdot \frac{\cancel{3}}{1} < 2 \cdot 3$ =

$7 x < 6$ =

Divide both sides by $7$.

$\frac{\cancel{7} x}{\cancel{7}} < \frac{6}{7}$ =

$x < \frac{6}{7}$