How do you solve 7x ^ { 3} + 5x - 2= 6x ^ { 3} + 5x - 3?

May 25, 2017

$x = - 1$

Explanation:

$7 {x}^{3} + 5 x - 2 = 6 {x}^{3} + 5 x - 3$
$7 {x}^{3} + \cancel{5 x} - 2 = 6 {x}^{3} + \cancel{5 x} - 3$
$7 {x}^{3} - 2 = 6 {x}^{3} - 3$
$7 {x}^{3} - 6 {x}^{3} = - 3 + 2$
${x}^{3} = - 1$
$x = \sqrt[3]{- 1} = - 1$
$x = - 1$