How do you solve #7x+6=2+3x#?

2 Answers
G_Ozdilek
May 7, 2018

By arranging the equation

Explanation:

Collect x terms on the left hand side and numerics on the other:

#7x + 6 = 2 + 3x

#7x - 3x = 2-6#

#4x = -4#

#x = -4/4 = -1#

Your answer is #x=-1#

Jim G.
May 7, 2018

#x=-1#

Explanation:

#"collect terms in x on the left side of the equation"#
#"and numeric values on the right side"#

#"subtract "3x" from both sides"#

#7x-3x+6=2cancel(+3x)cancel(-3x)#

#rArr4x+6=2#

#"subtract 6 from both sides"#

#4xcancel(+6)cancel(-6)=2-6#

#rArr4x=-4#

#"divide both sides by 4"#

#(cancel(4) x)/cancel(4)=(-4)/4#

#rArrx=-1#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=-7+6=-1#

#"right side "=2-3=-1#

#rArrx=-1" is the solution"#

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