How do you solve #-8(1/4n-3)=n+2#?

1 Answer
Jun 30, 2017

#n=22/3#

Explanation:

To solve this, we need to isolate the variable (#n#) on one side, and move everything else on the other side.

First, we can use the distributive property to simplify the left side of the equation:
#-8(1/4n-3)=n+2#
#-8(1/4n)-(-8)(3)=n+2#
#-2n-(-24)=n+2#
#-2n+24=n+2#

Adding #2n# to both sides, we have:
#24=3n+2#

Subtracting 2 from both sides, we have:
#22=3n#

Dividing by 3 gives:
#\frac{22}{3}=n#