How do you solve 8(10)^x + 2 = 26?

1 Answer
Jun 24, 2018

x=log_10(3)~~0.477

Explanation:

First, rewrite to the from a^x=b. Then use x=log_a(b).


8(10)^x+2=26

Subtract 2 from both sides.

8(10)^x=24

Divide both sides by 8.

10^x=3

Take the common logarithm (log with base 10) of both sides.

log_10(10^x)=log_10(3)

By definition: log_a(a^x)=x, so:

x=log_10(3)~~0.477