# How do you solve 8(3a-b) + 4(2b-a)?

Jun 18, 2018

See a solution process below:

#### Explanation:

To simplify this expression, first eliminate the parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:

$\textcolor{red}{8} \left(3 a - b\right) + \textcolor{b l u e}{4} \left(2 b - a\right) \implies$

$\left(\textcolor{red}{8} \times 3 a\right) - \left(\textcolor{red}{8} \times b\right) + \left(\textcolor{b l u e}{4} \times 2 b\right) - \left(\textcolor{b l u e}{4} \times a\right) \implies$

$24 a - 8 b + 8 b - 4 a$

Next, group like terms:

$24 a - 4 a - 8 b + 8 b$

Now, combine like terms:

$\left(24 - 4\right) a + \left(- 8 + 8\right) b \implies$

$20 a + 0 b \implies$

$20 a$