How do you solve #8( - 3x - 4) + 12= 28#?

1 Answer
Dec 25, 2016

#x = -2#

Explanation:

First, expand the terms within parenthesis by multiplying by the term outside the parenthesis - #color(red)(8)#:

#(color(red)(8) * (-3x)) + (color(red)(8) * (-4)) + 12 = 28#

#-24x - 32 + 12 = 28#

We can now add the constants on the left side of the equation:

#-24x - 20 = 28#

Next, we can isolate the #x# term on the left side of the equation by adding #color(blue)(20)# to each side of the equation which will also keep the equation balanced:

#-24x - 20 + color(blue)(20) = 28 + color(blue)(20)#

#-24x - 0 = 48#

#-24x = 48#

Now, we can solve for #x# by dividing each side of the equation by #color(green)(-24)# which will also keep the equation balanced:

#(-24x)/color(green)(-24) = 48/color(green)(-24)#

#(color(green)(cancel(color(black)(-24)))x)/cancel(color(green)(-24)) = -2#

#x = -2#