# How do you solve 8-5(x+3)=2?

Jun 14, 2018

Expand the bracket

$8 - 5 x - 15 = 2$

collect like terms

$- 5 x - 7 = 2$

add $5 x$

$- 7 = 2 + 5 x$

subtract 2

$- 9 = 5 x$

divide by 5

$- \frac{9}{5} = x$

Jun 14, 2018

$x = - \frac{9}{5}$

#### Explanation:

$\text{distribute bracket and simplify}$

$8 - 5 x - 15 = 2$

$- 5 x - 7 = 2$

$\text{add 7 to both sides}$

$- 5 x = 2 + 7 = 9$

$\text{divide both sides by } - 5$

$x = \frac{9}{- 5} = - \frac{9}{5}$

$\textcolor{b l u e}{\text{As a check}}$

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

$8 - 5 \left(- \frac{9}{5} + \frac{15}{5}\right) = 8 - \left(5 \times \frac{6}{5}\right) = 8 - 6 = 2$

$x = - \frac{9}{5} \text{ is the solution}$

Jun 14, 2018

$x = - \frac{9}{5} = - 1.8$

#### Explanation:

1) Eliminate the brackets: Multiply the $- 5$ into the bracket.

$- 5 \left(x\right) \text{ }$ and $\text{ } - 5 \left(3\right)$

You should get:

$8 - 5 x - 15 = 2$

2) Common Factor: Take the $8$ and add it to $- 15$.

$- 15 + 8$

You should get:

$- 5 x - 7 = 2$

3) Get the $x$ alone: Take the $- 7$ over to the other side so it turns into a positive:

$- 5 x = 2 + 7$

$- 5 x = 9$

Then to get the $x$ completely alone, you have to divide both sides by $- 5$ because the opposite of multiplication is division and what you do to one side, you have to do to the other.

You should get:

$x = \frac{9}{-} 5 = - 1.8$

Jun 14, 2018

$x = - \frac{9}{5}$

#### Explanation:

Let's start by distributing the $- 5$ to both of the terms in parenthesis. Doing this, we will get:

$- 5 x + 8 - 15 = 2$

Which simplifies to

$- 5 x - 7 = 2$

Adding $7$ to both sides gives us

$- 5 x = 9$

Lastly, dividing both sides by $- 5$, we get

$x = - \frac{9}{5}$

Hope this helps!