# How do you solve 8(k+2)=1?

Jul 7, 2018

$k = - \frac{15}{8}$

#### Explanation:

Dividing the whole equation by $8$ we get

$k + 2 = \frac{1}{8}$

subtracting $1$

$k = \frac{1}{8} - 2 = \frac{1}{8} - \frac{16}{8} = - \frac{15}{8}$

Jul 7, 2018

$k = - \frac{15}{8}$

#### Explanation:

$\text{divide both sides by 8}$

$k + 2 = \frac{1}{8}$

$\text{subtract 2 from both sides}$

$k = \frac{1}{8} - 2 = \frac{1}{8} - \frac{16}{8} = - \frac{15}{8}$

Jul 8, 2018

$k = - \frac{15}{8}$

#### Explanation:

Let's divide both sides by $8$ to begin isolating the $k$ term. We get

$k + 2 = \frac{1}{8}$

We can next subtract $2$ from both sides to get

$k = \frac{1}{8} - \frac{16}{8} = - \frac{15}{8}$

Thus, $k = - \frac{15}{8}$

Hope this helps!