How do you solve #8(x + 1)> 7(x + 2)#?

1 Answer
Jul 21, 2017

See a solution process below:

Explanation:

First, expand the terms within parenthesis on both sides of the inequality by multiplying each term within the parenthesis by the term outside the parenthesis:

#color(red)(8)(x + 1) > color(blue)(7)(x + 2)#

#(color(red)(8) xx x) + (color(red)(8) xx 1) > (color(blue)(7) xx x) + (color(blue)(7) xx 2)#

#8x + 8 > 7x + 14#

Now, subtract #color(red)(8)# and #color(blue)(7x)# from each side of the inequality to solve for #x# while keeping the inequality balanced:

#-color(blue)(7x) + 8x + 8 - color(red)(8) > -color(blue)(7x) + 7x + 14 - color(red)(8)#

#(-color(blue)(7) + 8)x + 0 > 0 + 6#

#1x > 6#

#x > 6#