How do you solve #8^ { - x } - 2.4^ { x - 1} = 0#?

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Answer 1 · 2018-01-30T16:00:55

#x=1/5#

#8^(-x)-2*4^(x-1)=0#

#2*4^(x-1)=8^(-x)#

#2*(2^2)^(x-1)=(2^3)^(-x)#

#2^[1+2*(x-1)]=2^(-3x)#

#2^(2x-1)=2^(-3x)#

#2x-1=-3x#

#5x=1#, so #x=1/5#