How do you solve 81-49n (49n to the fourth power)?

Question

81-49n

hash -49^4+ 81 hash gives: #-49n^4+81#

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Answer 1 · 2018-05-12T20:17:04

#n=(3sqrt(7))/7#

As written you can not solve this. It need to be 'equated' to some value.

Suppose you meant #-49n^4+81=0#

Subtract 81 from both sides

#-49n^4=-81#

Multiply both sides by (-1)

#49n^4=81#

Divide both sides by 49

#n^4=81/49#

#n=root(4)(81/49)#

#n=sqrt(9/7)#

#n=3/sqrt(7)#

#n= 3/sqrt(7)xxsqrt7/sqrt7 = (3sqrt(7))/7#