# How do you solve -8x + 10= - 6x + 20?

##### 2 Answers
Mar 3, 2018

$x = - 5$

#### Explanation:

We can start by adding $8 x$ to both sides of the equation. We get:

$10 = 2 x + 20$

We can subtract $20$ from both sides to get:

$- 10 = 2 x$

Switching the sides...

$2 x = - 10$

We can divide both sides by $2$ to get:

$x = - 5$

Mar 3, 2018

$x = - 5$

#### Explanation:

As with any equation, we always want $x$ on one side. Therefore we would either $+ 8 x$ or $+ 6 x$ to cancel out one of the $x ' s$ on any side, depending on what you choose to add. As adding $8 x$ would make the $- 6 x$ positive I will choose to $+ 8 x$.

$- 8 x + 10 = - 6 x + 20 \to 10 = 2 x + 20$

As want $x$ on its own, we $- 20$ from both sides, as this would cancel the $+ 20$ on the side with the $x$, getting rid of it. Always remember, what you do to one side, you must do to the other.

$10 = 2 x + 20 \to 2 x = - 10$

To solve an equation like this, we always divide the value by the value of $x ' s$.

$x = - \frac{10}{2} = - 5$

$\therefore$ $x = - 5$