How do you solve #8x^2-2x-5=0# using the quadratic formula?

1 Answer
May 12, 2018

Answer:

#color(blue)("Two roots are " x = (1 + sqrt(41)) / 8, (1 - sqrt(41)) / 8#

Explanation:

#"Quadratic Formula : "x = (-b +- sqrt(b^2 - 4ac)) / (2a)#

#"Given " 8x^2 - 2x - 5 = 0#

#a = 8, b = -2, c = -5#

Substituting values of a, b, c in the quadratic formula,

#x = (2 +- sqrt(4 + (4 * 8 * 5))) / (2 * 8)#

#x = (2 +- sqrt(164)) / 16#

#color(blue)(x = (1 +- sqrt(41)) / 8#