How do you solve #8x^2-38x=4# using the quadratic formula?
1 Answer
Jun 17, 2017
#x=-0.1025#
#x=4.85#
Explanation:
Given -
#8x^2-38x-4=0#
#x=(-b+-sqrt(b^2-4ac))/(2a)#
#a = 8#
#b=-38#
#c=-4#
#x=(-(38)+-sqrt(-38^2-(4xx8xx-4)))/(2xx8#
#x=(38+-sqrt(1444-(-128)))/16#
#x=(38+-sqrt(1572))/16#
#x=(38+-39.64)/16#
#x=(38-39.64)/16=(-1.64)/16=-0.1025#
#x=(38+39.64)/16=(77.64)/16=4.85#
#x=-0.1025#
#x=4.85#
