How do you solve 8x^2 - 5x - 3 = 0 by completing the square?

Aug 16, 2016

$x = 1 , - \frac{3}{8}$

Explanation:

$8 {x}^{2} - 5 x = 3$

${x}^{2} - \frac{5}{8} x = \frac{3}{8}$

${x}^{2} - \frac{10}{16} x = \frac{3}{8}$

${x}^{2} - \frac{10}{16} x + \frac{25}{256} = \frac{3}{8} + \frac{25}{256}$

${\left(x - \frac{5}{16}\right)}^{2} = \frac{121}{256}$

$x - \frac{5}{16} = \pm \frac{11}{16}$

$x = \left(\pm \frac{11}{16}\right) + \frac{5}{16}$

$x = \frac{5 \pm 11}{16}$

$x = 1 , - \frac{3}{8}$