How do you solve #8x^2-6x+1=0#?
Factorise the quadratic trinomial and then let each factor be equal to 0.
(Find factors of 8 which add up 6.)
In any equation with the form of:
Then, there are three different cases of finding the roots depending on the discriminant
No1: if D < 0 then the equation has no rootes
No2: if D = 0 then the equation has one answer which you can find using
No3: if D>0 then the equation has two roots which you can find using
Let's take your example: