How do you solve #-9= 5- 3c + 4#?

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Answer 1 · 2017-07-16T15:13:14

See a solution process below:

First, group and combine like terms (in this problem the constants) on the right side of the equation:

#-9 = 5 + 4 - 3c#

#-9 = 9 - 3c#

Next, subtract #color(red)(9)# from each side of the equation to isolate the #c# term while keeping the equation balanced:

#-color(red)(9) - 9 = -color(red)(9) + 9 - 3c#

#-18 = 0 - 3c#

#-18 = -3c#

Now, divide each side of the equation by #color(red)(-3)# to solve for #c# while keeping the equation balanced:

#(-18)/color(red)(-3) = (-3c)/color(red)(-3)#

#6 = (color(red)(cancel(color(black)(-3)))c)/cancel(color(red)(-3))#

#6 = c#

#c = 6#