How do you solve # 9< | c + 7|#?

1 Answer
Oct 2, 2016

#c>2# or #c<-16#

Explanation:

Let's see it the other way: #|c+7|>9#. I think this is more helpful, because we know that if #|x|>\alpha#, then one between #x<-\alpha# and #x>\alpha# must hold.

So, in your case, we have two possibilities:

  • #c+7>9#, which yields #c>2#

  • #c+7<-9#, which yields #c<-16#

In other words, we want the quantity #c+7# to be, in an absolute sense, larger than #9#. This means that it has to be very large (#>9#), or very small (#<-9#), since the absolute always return the positive version of the number, and thus it is true that #|-25|>9#, because it means #25>9#.