How do you solve #9+ \frac { k } { 2} >= 5#?

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Answer 1 · 2017-03-20T17:37:45

See the entire solution below:

First, subtract #color(red)(9)# from each side of the inequality to isolate the #k# term while keeping the inequality balanced:

#-color(red)(9) + 9 + k/2 >= -color(red)(9) + 5#

#0 + k/2 >= -4#

#k/2 >= -4#

Now, multiply each side of the equation by #color(red)(2)# to solve for #k# while keeping the inequality balanced:

#color(red)(2) xx k/2 >= color(red)(2) xx -4#

#cancel(color(red)(2)) xx k/color(red)(cancel(color(black)(2))) >= -8#

#k >= -8#