# How do you solve 9^x=45?

Oct 15, 2017

$x \approx 1.73$
You can log both sides of the equation to bring $x$ down.
$\log {9}^{x} = \log 45$
$x \log 9 = \log 45$
$x = \log \frac{45}{\log} 9$
$x \approx 1.73 \rightarrow$ to $3$ s.f