# How do you solve 9v^2-8=0 using the quadratic formula?

$\frac{2 \sqrt{2}}{3}$
$v = - b \pm \frac{\sqrt{{b}^{2} - 4 a c}}{2 a} = 0 \pm \frac{\sqrt{0 - 4 \cdot \left(9\right) \cdot \left(- 8\right)}}{2 \cdot \left(9\right)} = \pm \frac{\sqrt{288}}{18} = \pm \frac{\sqrt{2 \cdot 2 \cdot 2 \cdot 2 \cdot 2 \cdot 3 \cdot 3}}{18} = \frac{12 \sqrt{2}}{18} = \frac{2 \sqrt{2}}{3}$