How do you solve #(9w+11)(w +9)=79#?

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Answer 1 · 2016-11-12T00:25:52

The two answers are:
#w=-2/9#
#w=-10#

#(9w+11)(w+9)=79#

In order to make a quadratic equation where one side equals zero, first multiply out, or FOIL, the left side:
#9w^2+81w+11w+99=79#

Simplify by combining like terms, and setting one side equal to zero.
#9w^2+92w+20=0#

Solve by factoring:
#9w^2+90w+2w+20=0#

#9w(w+10)+2(w+10)=0#

#(9w+2)(w+10)=0#

#w=-2/9#
#w=-10#