# How do you solve (9w+11)(w +9)=79?

Nov 12, 2016

$w = - \frac{2}{9}$
$w = - 10$

#### Explanation:

$\left(9 w + 11\right) \left(w + 9\right) = 79$

In order to make a quadratic equation where one side equals zero, first multiply out, or FOIL, the left side:
$9 {w}^{2} + 81 w + 11 w + 99 = 79$

Simplify by combining like terms, and setting one side equal to zero.
$9 {w}^{2} + 92 w + 20 = 0$

Solve by factoring:
$9 {w}^{2} + 90 w + 2 w + 20 = 0$

$9 w \left(w + 10\right) + 2 \left(w + 10\right) = 0$

$\left(9 w + 2\right) \left(w + 10\right) = 0$

$w = - \frac{2}{9}$
$w = - 10$