How do you solve #|9x + 1| < - 4#?

1 Answer
Dec 7, 2017

There is no solution.

Explanation:

Given:

#|9x + 1| < - 4#

Use the piecewise definition of the absolute value function

#|9x+1|={(9x+1; x >=-1/9),(-(9x+1);x < -1/9):}#

and separate the inequality into two inequalities:

#9x + 1 < - 4; x >= -1/9# and #-(9x+1)<-4; x < -1/9#

Multiply the second inequality by -1:

#9x + 1 < - 4; x >= -1/9# and #9x+1 > 4; x < -1/9#

Subtract 1 from both sides of both inequalities:

#9x < - 5; x >= -1/9# and #9x > 3; x < -1/9#

Divide both sides of both inequalities by 9:

#x < - 5/9; x >= -1/9# and #x > 1/3; x < -1/9#

Please observe that x cannot be less than #-5/9# and greater than or equal to #-1/9# and x cannot be greater than #1/3# and less than #-1/9#. Therefore, there is no solution.