How do you solve #9x^2=324#?

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Answer 1 · 2016-04-14T05:00:07

#x= +-6#

To solve #9x^2=324#

Begin by dividing both sides by #9# to isolate the term with #x#

#(cancel9x^2)/cancel9=324/9#

This gives us

#x^2=36#

Now square root both sides of the equation to
cancel the square of #x#

#sqrt(x^2)=sqrt36#

We get

#x= +-6#