How do you solve #9x + 5y = 28# and #5x + 9y = 56#?
This can be solved by elimination method. To do this, one can try eliminating x, by multiplying the first equation by 5 and the second equation by 9, then subtracting as follows:
1st eq becomes 45x +25y = 140
2nd eq becomes45x +81y= 504
On subtracting, -56y = -364
Using this value of y in the first equation,