How do you solve #9x + 7= 145#?

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Answer 1 · 2017-05-25T23:29:34

See a solution process below

First, subtract #color(red)(7)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#9x + 7 - color(red)(7) = 145 - color(red)(7)#

#9x + 0 = 138#

#9x = 138#

Now, divide each side of the equation by #color(red)(9)# to solve for #x# while keeping the equation balanced:

#(9x)/color(red)(9) = 138/9#

#(color(red)(cancel(color(black)(9)))x)/cancel(color(red)(9)) = 138/color(red)(9)#

#x = 138/9#

#x = (3 xx 46)(3 xx 3)#

#x = (color(red)(cancel(color(black)(3))) xx 46)(color(red)(cancel(color(black)(3))) xx 3)#

#x = 46/3#

Or

#x = 15.bar3#