How do you solve #a^2-2a-224=0#?
I use the new Transforming Method (Google Yahoo Search)
Find 2 numbers knowing sum (2) and product (-224). Roots have different signs.
Factor pairs of (-224) -> ...(-8, 28)(-14, 16). This sum is 2 = -b. Then, the 2 real roots are:
Factor the trinomial as the product of two binomials. Set each binomial equal to zero, and solve for
Find two numbers that when added equal