# How do you solve #a^2-2a-224=0#?

##### 2 Answers

Jul 8, 2015

Solve

#### Explanation:

I use the new Transforming Method (Google Yahoo Search)

Find 2 numbers knowing sum (2) and product (-224). Roots have different signs.

Factor pairs of (-224) -> ...(-8, 28)(-14, 16). This sum is 2 = -b. Then, the 2 real roots are:

Jul 8, 2015

Factor the trinomial as the product of two binomials. Set each binomial equal to zero, and solve for

#### Explanation:

Find two numbers that when added equal

Set

#a=16

Set