# How do you solve a^2-2a-24=0?

Jul 15, 2015

First you factorise

#### Explanation:

You find two numbers that have $24$ as a product, with a difference (because of the $-$sign) of $2$.
After some trying you will find $4 \mathmr{and} 6$:

$\left(a - 6\right) \left(a + 4\right) = 0 \to a = 6 \mathmr{and} a = - 4$