# How do you solve abs(2x-5)> -1?

Given $\left\mid 2 x - 5 \right\mid > - 1$
$\textcolor{w h i t e}{\text{XXXXX}}$$\left\mid \text{anything} \right\mid \ge 0$
$\textcolor{w h i t e}{\text{XXXXX}}$$\left\mid 2 x - 5 \right\mid > - 1$ is valid for any value of $x$
$\textcolor{w h i t e}{\text{XXXXX}}$ All $x \epsilon \mathbb{R}$ (or, actually, all $x \epsilon \mathbb{C}$ if you want to expand to complex numbers).