# How do you solve and graph  3(2x - 1) ≥ 4(2x - 3) - 3?

x \in ]-infty, 6]
$6 x - 3 \setminus \ge 8 x - 12 - 3$
$15 - 3 \setminus \ge 2 x$
$6 \setminus \ge x$