# How do you solve and graph 3x < -9 or x + 2 ≥ 10?

Mar 29, 2016

For, 1-D graph, it is real line sans the segment for $- 3 \le x < 8$..
The point x = 8 is included. The point x =$- 3$ is excluded.
$x < - 3 \mathmr{and} x > 8$.
For 2-D graph of {(x, y)}, y = 3x < $- 9$ and y = x + 2 > 10, draw the straight lines, $\pm 3$ and x + 8 parallel to the y-axis. Shade the region outside this strip, including the line x = 8. In this region, x is governed by the inequalities.