How do you solve and graph #abs((2g+3)/2)> -7#?
Solve the equation twice once for the positive value of the absolute value and once for the negative value of the absolute value and then graph the results.
subtract -3 from both sides
Draw an open circle at - 17/2 and a solid arrow going to the right.
Add +3 to both sides
# -2g -3 + 3 > -14 + 3 so
# g < + 11/2
Draw an open circle at + 11/2 and a solid arrow going to the left.
the graph will be the line between - 17/2 and + 11/2