# How do you solve and write the following in interval notation: -2x<3-x<=8?

Mar 28, 2017

x in ]-3;+oo[

#### Explanation:

Let's write and solve the equivalent:

$- 2 x < 3 - x \mathmr{and} 3 - x \le 8$

$2 x - x > - 3 \mathmr{and} x \ge 3 - 8$

$x > - 3 \mathmr{and} x \ge - 5$

that's

$x > - 3$

or, in interval notation:

x in ]-3;+oo[