# How do you solve and write the following in interval notation: 2x + 6 < 8?

Mar 18, 2018

See a solution process below:

#### Explanation:

First subtract $\textcolor{red}{6}$ from each side of the inequality to isolate the $x$ term while keeping the inequality balanced:

$2 x + 6 - \textcolor{red}{6} < 8 - \textcolor{red}{6}$

$2 x + 0 < 2$

$2 x < 2$

Now, divide each side of the inequality be $\textcolor{red}{2}$ to solve for $x$ while keeping the inequality balanced:

$\frac{2 x}{\textcolor{red}{2}} < \frac{2}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} x}{\cancel{\textcolor{red}{2}}} < 1$

$x < 1$

Or, in interval notation:

$\left(- \infty , 1\right)$