How do you solve and write the following in interval notation: #3x+3>21#?
1 Answer
Jun 17, 2017
Explanation:
#"isolate 3x by subtracting 3 from both sides"#
#3xcancel(+3)cancel(-3)>21-3#
#rArr3x>18#
#"divide both sides by 3"#
#(cancel(3) x)/cancel(3)>18/3#
#rArrx>6" is the solution"#
#"in interval notation " (6,+oo)#
