How do you solve and write the following in interval notation: # -5 <= 4x + 7#?
1 Answer
Mar 19, 2018
Explanation:
#"isolate 4x by subtracting 7 from both sides"#
#-5-7<=4xcancel(+7)cancel(-7)#
#rArr-12<=4x#
#"divide both sides by 4"#
#(-12)/4<=(cancel(4) x)/cancel(4)#
#rArr-3<=x" or "x>= -3#
#[-3,+oo)larrcolor(blue)"in interval notation"#
