How do you solve and write the following in interval notation: $6<= 4x-2<=26$ ?

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Answer 1 · 2016-07-21T17:31:31

$x in [2,7]$ .

$6<=4x-2<=26$ Adding $2$ ,

$8<=4x<=28$

Now we multiply the inequality by $1/4>0$ , so that, the sign will not be reversed. Hence,

$2<=x<=7$

$:.$ in the Interval Form, this is written as $x in [2,7]$ .

How do you solve and write the following in interval notation: 6<= 4x-2<=266<= 4x-2<=26?