# How do you solve (b+1)/3=2?

Mar 11, 2018

$b = 5$

#### Explanation:

We got: $\frac{b + 1}{3} = 2$

Multiplying both sides by $3$, we get

$\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}} \cdot \frac{b + 1}{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}} = 2 \cdot 3$

$b + 1 = 6$

Subtracting $1$ from both sides, we have

$b + \textcolor{red}{\cancel{\textcolor{b l a c k}{1}}} - \textcolor{red}{\cancel{\textcolor{b l a c k}{1}}} = 6 - 1$

$b = 5$

Mar 11, 2018

$b = 5$

#### Explanation:

$\frac{b + 1}{3} = 2$

Cross multiply

$b + 1 = \left(2\right) \left(3\right)$

$b + 1 = 6$

Subtract $1$ on both sides

$b + 1 - 1 = 6 - 1$

$b = 5$