How do you solve #b^2 + 5b - 35 = 3b# by factoring?

1 Answer
Aug 7, 2015

Answer:

Solve #y = b^2 + 5b - 35 = 3b#

Ans: #(b - 5)(b + 7)#

Explanation:

#y = b^2 + 2b - 35 = 0#
Find 2 numbers p and q knowing sum (b = 2) and product (c =-35).
p and q have opposite signs (Rule of signs)
Factor pairs of (-35) -->...(-1, 35) (-5, 7). This sum is 2 = b.
Then p = -5 and q = 7.

Factored form:# y = (b - 5)(b + 7)#