# How do you solve #bx^2-b = x-b^2x# by factoring?

##### 1 Answer

Aug 25, 2015

#### Explanation:

We can solve for **making Groups**

Transposing the terms on the right to the left, we get:

Next, we form groups of 2 terms:

Then we take the common factors out from each group

The factor

This tells us that :