How do you solve by completing the square for 3x^2-12x+1?

2 Answers
May 29, 2015

3x^2 -12x +1 if you add 8 than it will be like;
3x^2-12 +9 = (3x-3)*(x-3) this is as far as i get.
But i think that some info is missing with that question. To completely solve this question;
3x^2 -12x +1 = A => we should know this "A" value.
Since you didn't write that A value i cannot entirely solve the question . I 'm sorry :)

May 29, 2015

I will assume that what you really want to solve (by completing the square) is 3x^2-12x+1 = 0

3x^2-12x+1 = 0

x^2-4x = -1/3

x^2-4x+4 = 4-1/3

(x-2)^2 = 11/3

x-2 = +-sqrt(11)/sqrt(3)

x=2+sqrt(11)/sqrt(3) or x=2-sqrt(11)/sqrt(3)