Question

How do you solve by completing the square for `3x^2-12x+1`?

Answer 1

`3x^2 -12x +1` if you add 8 than it will be like;
`3x^2-12 +9 = (3x-3)*(x-3)` this is as far as i get.
But i think that some info is missing with that question. To completely solve this question;
`3x^2 -12x +1 = A =>` we should know this "A" value.
Since you didn't write that A value i cannot entirely solve the question . I 'm sorry :)

Answer 2

I will assume that what you really want to solve (by completing the square) is `3x^2-12x+1 = 0`

`3x^2-12x+1 = 0`

`x^2-4x = -1/3`

`x^2-4x+4 = 4-1/3`

`(x-2)^2 = 11/3`

`x-2 = +-sqrt(11)/sqrt(3)`

`x=2+sqrt(11)/sqrt(3)` or `x=2-sqrt(11)/sqrt(3)`